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6-5x=6x^2
We move all terms to the left:
6-5x-(6x^2)=0
determiningTheFunctionDomain -6x^2-5x+6=0
a = -6; b = -5; c = +6;
Δ = b2-4ac
Δ = -52-4·(-6)·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-13}{2*-6}=\frac{-8}{-12} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+13}{2*-6}=\frac{18}{-12} =-1+1/2 $
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